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60=30x^2
We move all terms to the left:
60-(30x^2)=0
a = -30; b = 0; c = +60;
Δ = b2-4ac
Δ = 02-4·(-30)·60
Δ = 7200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7200}=\sqrt{3600*2}=\sqrt{3600}*\sqrt{2}=60\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60\sqrt{2}}{2*-30}=\frac{0-60\sqrt{2}}{-60} =-\frac{60\sqrt{2}}{-60} =-\frac{\sqrt{2}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60\sqrt{2}}{2*-30}=\frac{0+60\sqrt{2}}{-60} =\frac{60\sqrt{2}}{-60} =\frac{\sqrt{2}}{-1} $
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